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Problem Statement: Palindrome Of A Number Program Solution | leetcode Program Solution
Given an integer x, return true if x is palindrome integer.
An integer is a palindrome when it reads the same backward as forward.
- For example,
121is a palindrome while123is not.
Example 1:
Input: x = 121 Output: true Explanation: 121 reads as 121 from left to right and from right to left.
Example 2:
Input: x = -121 Output: false Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10 Output: false Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Constraints:
-231 <= x <= 231 - 1
- Time: O(\log x)O(logx)
- Space: O(\log x)O(logx)
Palindrome Of A Number Program Solution In C++
class Solution {
public:
bool isPalindrome(int x) {
if (x < 0)
return false;
long reversed = 0;
int y = x;
while (y) {
reversed = reversed * 10 + y % 10;
y /= 10;
}
return reversed == x;
}
};
Palindrome Of A Number Program Solution In JAVA
class Solution {
public boolean isPalindrome(int x) {
if (x < 0)
return false;
long reversed = 0;
int y = x;
while (y > 0) {
reversed = reversed * 10 + y % 10;
y /= 10;
}
return reversed == x;
}
}
Palindrome Of A Number Program Solution In PYTHON
class Solution:
def isPalindrome(self, x: int) -> bool:
if x < 0:
return False
rev = 0
y = x
while y:
rev = rev * 10 + y % 10
y //= 10
return rev == x
