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Problem Statement: Palindrome Of A Number Program Solution | leetcode Program Solution

Given an integer `x`

, return `true`

if `x`

is palindrome integer.

An integer is a **palindrome** when it reads the same backward as forward.

- For example,
`121`

is a palindrome while`123`

is not.

**Example 1:**

Input:x = 121Output:trueExplanation:121 reads as 121 from left to right and from right to left.

**Example 2:**

Input:x = -121Output:falseExplanation:From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

**Example 3:**

Input:x = 10Output:falseExplanation:Reads 01 from right to left. Therefore it is not a palindrome.

**Constraints:**

`-2`

^{31}<= x <= 2^{31}- 1

**Time:**O(\log x)*O*(log*x*)**Space:**O(\log x)*O*(log*x*)

### Palindrome Of A Number Program Solution In C++

```
class Solution {
public:
bool isPalindrome(int x) {
if (x < 0)
return false;
long reversed = 0;
int y = x;
while (y) {
reversed = reversed * 10 + y % 10;
y /= 10;
}
return reversed == x;
}
};
```

### Palindrome Of A Number Program Solution In JAVA

```
class Solution {
public boolean isPalindrome(int x) {
if (x < 0)
return false;
long reversed = 0;
int y = x;
while (y > 0) {
reversed = reversed * 10 + y % 10;
y /= 10;
}
return reversed == x;
}
}
```

### Palindrome Of A Number Program Solution In PYTHON

```
class Solution:
def isPalindrome(self, x: int) -> bool:
if x < 0:
return False
rev = 0
y = x
while y:
rev = rev * 10 + y % 10
y //= 10
return rev == x
```