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Problem Statment
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123 Output: 321
Example 2:
Input: x = -123 Output: -321
Example 3:
Input: x = 120 Output: 21
- Time: O(\log x)O(logx)
- Space: O(1)O(1)
REVERSE INTEGER PROGRAM SOLUTION IN C++
class Solution {
public:
int reverse(int x) {
long ans = 0;
while (x) {
ans = ans * 10 + x % 10;
x /= 10;
}
return (ans < INT_MIN || ans > INT_MAX) ? 0 : ans;
}
};
REVERSE INTEGER PROGRAM SOLUTION IN JAVA
class Solution {
public int reverse(int x) {
long ans = 0;
while (x != 0) {
ans = ans * 10 + x % 10;
x /= 10;
}
return (ans < Integer.MIN_VALUE || ans > Integer.MAX_VALUE) ? 0 : (int) ans;
}
}
REVERSE INTEGER PROGRAM SOLUTION IN PYTHON
class Solution:
def reverse(self, x: int) -> int:
ans = 0
sign = -1 if x < 0 else 1
x *= sign
while x:
ans = ans * 10 + x % 10
x //= 10
return 0 if ans < -2**31 or ans > 2**31 - 1 else sign * ans
