TCS NQT EYE TEST CODING PROBLEM SOLUTION

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Problem Statement

An organisation is conducting an eye check-up camp, the number of people allowed for registration is 10. A person is supposed to enter his age for registration. If a senior s=citizen above 60 years of age registers then he is shifted to another queue which will be the 2nd queue, now 2 separate queues are created for a check-up. The 2nd queue will be for senior citizens. If the number of people in the 2nd queue becomes 5 then shifting senior citizens from the 1st queue to the 2nd is stopped. Suppose an eye check-up takes approx. 15 min per person, then calculate the total time taken for a check-up by first and queue resp. The number of people who will be registered ‘N’ will be input:

1 <= N <= 10 and Age of a person ‘A’ 10 <= A <= 100

Note:

1. Output should be in the format:

QUEUE1 TIME: <integer> mins

QUEUE2 TIME: <integer> mins

If the age is below 10 or above 100, display “INVALID INPUT”

**Algorithm**

“`

1. Read N.

2. Declare q1 and q2 and set both variables to 0.

3. for i from 0 to n – 1 inclusive, do,

    Read age.

    if age > 100 or age < 10, do

        Print INVALID INPUT

        exit

    if age > 60 and q2 < 5, do

        q2 = q2 + 1

    else, do,

        q1 = q1 + 1

4. Print QUEUE1 TIME: (q1 * 15)

5. Print QUEUE2 TIME: (q2 * 15)

“`

Program in C

#include <stdio.h>
int main()
{
    int n, q1 = 0, q2 = 0, age;
    scanf("%d", &n);
    while (n--)
    {
        scanf("%d", &age);
        if (age > 100 || age < 10)
        {
            printf("INVALID INPUT");
            return 0;
        }
        if (age > 60 && q2 < 5)
            q2 += 1;
        else
            q1 += 1;
    }
    printf("QUEUE1 TIME: %d\n", q1 * 15);
    printf("QUEUE2 TIME: %d", q2 * 15);
}

Program in C++

#include <iostream>

using std::cin;
using std::cout;
using std::endl;

int main() {
	int n, q1 {0}, q2 {0}, age;
	cin >> n;
	while (n--) {
		cin >> age;
		if ( age > 100 || age < 10 ) {
			cout << "INVALID INPUT";
			return 0;
		}
		if ( age > 60 && q2 < 5 )
			q2 += 1;
		else
			q1 += 1;
	}
	cout << "QUEUE1 TIME: " << q1 * 15 << endl;
	cout << "QUEUE2 TIME: " << q2 * 15;
	return 0;
}

Program in Java

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int age, q1 = 0, q2 = 0;
        while(n > 0)
        {
            age = in.nextInt();
            if (age > 100 || age < 10)
            {
                System.out.print("INVALID INPUT");
                System.exit(0);
            }
            if (age > 60 && q2 < 5)
                q2 += 1;
            else
                q1 += 1;
            n--;
        }
        System.out.println("QUEUE1 TIME: "+ q1 * 15);
        System.out.print("QUEUE2 TIME: "+ q2 * 15);
    }
}

Program in Python

if __name__ == "__main__":
    n = int(input())
    q1 = 0
    q2 = 0
    for _ in range(n):
        age = int(input())
        if age > 100 or age < 10:
            print("INVALID INPUT")
            exit(0)
        if age > 60 and q2 < 5:
            q2 += 1
        else:
            q1 += 1
    print("QUEUE1 TIME:", q1 * 15)
    print("QUEUE2 TIME:", q2 * 15)

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