Write an SQL query to find all dates’ Id with higher temperatures compared to its previous dates (yesterday).
Table: Weather
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | recordDate | date | | temperature | int | +---------------+---------+ id is the primary key for this table. This table contains information about the temperature on a certain day.
Write an SQL query to find all dates Id with higher temperatures compared to its previous dates (yesterday).
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input: Weather table: +----+------------+-------------+ | id | recordDate | temperature | +----+------------+-------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +----+------------+-------------+ Output: +----+ | id | +----+ | 2 | | 4 | +----+ Explanation: In 2015-01-02, the temperature was higher than the previous day (10 -> 25). In 2015-01-04, the temperature was higher than the previous day (20 -> 30).
——————————————————————————– SOLUTION ——————————————————————————–
select w2.id
from Weather w1 JOIN Weather w2 ON DATEDIFF(w1.recordDate, w2.recordDate)= -1
WHERE w2.temperature > w1.temperature